Base | Representation |
---|---|
bin | 111100100011110111… |
… | …0001100110010101001 |
3 | 110102200120100222111221 |
4 | 1321013232030302221 |
5 | 4112321342442413 |
6 | 135424544222041 |
7 | 12252550262104 |
oct | 1710756146251 |
9 | 412616328457 |
10 | 130052312233 |
11 | 5017815a088 |
12 | 2125630a921 |
13 | c35798c50c |
14 | 641a40573b |
15 | 35b274868d |
hex | 1e47b8cca9 |
130052312233 has 2 divisors, whose sum is σ = 130052312234. Its totient is φ = 130052312232.
The previous prime is 130052312219. The next prime is 130052312237. The reversal of 130052312233 is 332213250031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112377141529 + 17675170704 = 335227^2 + 132948^2 .
It is a cyclic number.
It is not a de Polignac number, because 130052312233 - 29 = 130052311721 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130052312198 and 130052312207.
It is not a weakly prime, because it can be changed into another prime (130052312237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026156116 + 65026156117.
It is an arithmetic number, because the mean of its divisors is an integer number (65026156117).
Almost surely, 2130052312233 is an apocalyptic number.
It is an amenable number.
130052312233 is a deficient number, since it is larger than the sum of its proper divisors (1).
130052312233 is an equidigital number, since it uses as much as digits as its factorization.
130052312233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 130052312233 its reverse (332213250031), we get a palindrome (462265562264).
The spelling of 130052312233 in words is "one hundred thirty billion, fifty-two million, three hundred twelve thousand, two hundred thirty-three".
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