Base | Representation |
---|---|
bin | 11101100100100000111000… |
… | …001111010010010101000101 |
3 | 122001110220101001020012201112 |
4 | 131210200320033102111011 |
5 | 114021240112113113323 |
6 | 1140333152420334405 |
7 | 36251662336043162 |
oct | 3544407017222505 |
9 | 561426331205645 |
10 | 130052553254213 |
11 | 38490a83937a27 |
12 | 12705080b44405 |
13 | 5774b982aba05 |
14 | 2418811a43069 |
15 | 1007e73188178 |
hex | 7648383d2545 |
130052553254213 has 2 divisors, whose sum is σ = 130052553254214. Its totient is φ = 130052553254212.
The previous prime is 130052553254209. The next prime is 130052553254219. The reversal of 130052553254213 is 312452355250031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130052538867364 + 14386849 = 11404058^2 + 3793^2 .
It is a cyclic number.
It is not a de Polignac number, because 130052553254213 - 22 = 130052553254209 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130052553254219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026276627106 + 65026276627107.
It is an arithmetic number, because the mean of its divisors is an integer number (65026276627107).
Almost surely, 2130052553254213 is an apocalyptic number.
It is an amenable number.
130052553254213 is a deficient number, since it is larger than the sum of its proper divisors (1).
130052553254213 is an equidigital number, since it uses as much as digits as its factorization.
130052553254213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 130052553254213 in words is "one hundred thirty trillion, fifty-two billion, five hundred fifty-three million, two hundred fifty-four thousand, two hundred thirteen".
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