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130052553254213 is a prime number
BaseRepresentation
bin11101100100100000111000…
…001111010010010101000101
3122001110220101001020012201112
4131210200320033102111011
5114021240112113113323
61140333152420334405
736251662336043162
oct3544407017222505
9561426331205645
10130052553254213
1138490a83937a27
1212705080b44405
135774b982aba05
142418811a43069
151007e73188178
hex7648383d2545

130052553254213 has 2 divisors, whose sum is σ = 130052553254214. Its totient is φ = 130052553254212.

The previous prime is 130052553254209. The next prime is 130052553254219. The reversal of 130052553254213 is 312452355250031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130052538867364 + 14386849 = 11404058^2 + 3793^2 .

It is a cyclic number.

It is not a de Polignac number, because 130052553254213 - 22 = 130052553254209 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130052553254219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026276627106 + 65026276627107.

It is an arithmetic number, because the mean of its divisors is an integer number (65026276627107).

Almost surely, 2130052553254213 is an apocalyptic number.

It is an amenable number.

130052553254213 is a deficient number, since it is larger than the sum of its proper divisors (1).

130052553254213 is an equidigital number, since it uses as much as digits as its factorization.

130052553254213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 130052553254213 in words is "one hundred thirty trillion, fifty-two billion, five hundred fifty-three million, two hundred fifty-four thousand, two hundred thirteen".