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13005301403 is a prime number
BaseRepresentation
bin11000001110010110…
…10010011010011011
31020120100202202121202
430013023102122123
5203113324121103
65550300424415
7640166144423
oct140713223233
936510682552
1013005301403
115574176486
12262b54810b
1312c3509a23
148b5349483
15511b4c988
hex3072d269b

13005301403 has 2 divisors, whose sum is σ = 13005301404. Its totient is φ = 13005301402.

The previous prime is 13005301399. The next prime is 13005301433. The reversal of 13005301403 is 30410350031.

It is a happy number.

13005301403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13005301403 - 22 = 13005301399 is a prime.

It is a super-3 number, since 3×130053014033 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13005301433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502650701 + 6502650702.

It is an arithmetic number, because the mean of its divisors is an integer number (6502650702).

Almost surely, 213005301403 is an apocalyptic number.

13005301403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13005301403 is an equidigital number, since it uses as much as digits as its factorization.

13005301403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 13005301403 its reverse (30410350031), we get a palindrome (43415651434).

The spelling of 13005301403 in words is "thirteen billion, five million, three hundred one thousand, four hundred three".