Base | Representation |
---|---|
bin | 10010111011001101101… |
… | …111111010100101111100 |
3 | 11121022220022102112110111 |
4 | 102323031233322211330 |
5 | 132301442143412221 |
6 | 2433242310315404 |
7 | 162650252501065 |
oct | 22731557724574 |
9 | 4538808375414 |
10 | 1300532013436 |
11 | 461609464817 |
12 | 190075658b64 |
13 | 958413aaaa6 |
14 | 46d360b556c |
15 | 23c6a9b3be1 |
hex | 12ecdbfa97c |
1300532013436 has 12 divisors (see below), whose sum is σ = 2285374722400. Its totient is φ = 647567807040.
The previous prime is 1300532013433. The next prime is 1300532013457. The reversal of 1300532013436 is 6343102350031.
It is a junction number, because it is equal to n+sod(n) for n = 1300532013398 and 1300532013407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300532013433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 674548836 + ... + 674550763.
Almost surely, 21300532013436 is an apocalyptic number.
It is an amenable number.
1300532013436 is a deficient number, since it is larger than the sum of its proper divisors (984842708964).
1300532013436 is a wasteful number, since it uses less digits than its factorization.
1300532013436 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1349099844 (or 1349099842 counting only the distinct ones).
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 1300532013436 its reverse (6343102350031), we get a palindrome (7643634363467).
The spelling of 1300532013436 in words is "one trillion, three hundred billion, five hundred thirty-two million, thirteen thousand, four hundred thirty-six".
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