Base | Representation |
---|---|
bin | 11101100100100001101100… |
… | …100101010000001111111011 |
3 | 122001110222122020200001210222 |
4 | 131210201230211100033323 |
5 | 114021243411421144331 |
6 | 1140333415510530255 |
7 | 36252023161305653 |
oct | 3544415445201773 |
9 | 561428566601728 |
10 | 130053431428091 |
11 | 38491394611a66 |
12 | 1270528706698b |
13 | 5774ca8202a22 |
14 | 241889651b363 |
15 | 1007ec5302b7b |
hex | 76486c9503fb |
130053431428091 has 2 divisors, whose sum is σ = 130053431428092. Its totient is φ = 130053431428090.
The previous prime is 130053431428069. The next prime is 130053431428097. The reversal of 130053431428091 is 190824134350031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130053431428091 is a prime.
It is not a weakly prime, because it can be changed into another prime (130053431428097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026715714045 + 65026715714046.
It is an arithmetic number, because the mean of its divisors is an integer number (65026715714046).
Almost surely, 2130053431428091 is an apocalyptic number.
130053431428091 is a deficient number, since it is larger than the sum of its proper divisors (1).
130053431428091 is an equidigital number, since it uses as much as digits as its factorization.
130053431428091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 44.
The spelling of 130053431428091 in words is "one hundred thirty trillion, fifty-three billion, four hundred thirty-one million, four hundred twenty-eight thousand, ninety-one".
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