Base | Representation |
---|---|
bin | 11101100100100001101100… |
… | …101101010000001111111011 |
3 | 122001110222122101121121120021 |
4 | 131210201230231100033323 |
5 | 114021243412440301433 |
6 | 1140333420023511311 |
7 | 36252023215162054 |
oct | 3544415455201773 |
9 | 561428571547507 |
10 | 130053433525243 |
11 | 38491395814648 |
12 | 127052878b8537 |
13 | 5774ca8788447 |
14 | 241889690572b |
15 | 1007ec55b922d |
hex | 76486cb503fb |
130053433525243 has 2 divisors, whose sum is σ = 130053433525244. Its totient is φ = 130053433525242.
The previous prime is 130053433525163. The next prime is 130053433525273. The reversal of 130053433525243 is 342525334350031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130053433525243 - 221 = 130053431428091 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130053433525243.
It is not a weakly prime, because it can be changed into another prime (130053433525273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026716762621 + 65026716762622.
It is an arithmetic number, because the mean of its divisors is an integer number (65026716762622).
Almost surely, 2130053433525243 is an apocalyptic number.
130053433525243 is a deficient number, since it is larger than the sum of its proper divisors (1).
130053433525243 is an equidigital number, since it uses as much as digits as its factorization.
130053433525243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944000, while the sum is 43.
Adding to 130053433525243 its reverse (342525334350031), we get a palindrome (472578767875274).
The spelling of 130053433525243 in words is "one hundred thirty trillion, fifty-three billion, four hundred thirty-three million, five hundred twenty-five thousand, two hundred forty-three".
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