Base | Representation |
---|---|
bin | 111100100100010001… |
… | …0101100110000010011 |
3 | 110102201112021011222211 |
4 | 1321020202230300103 |
5 | 4112333403342033 |
6 | 135430155212551 |
7 | 12253105251541 |
oct | 1711042546023 |
9 | 412645234884 |
10 | 130066074643 |
11 | 501849a9a7a |
12 | 2125aa47157 |
13 | c35a79a75b |
14 | 641c188d91 |
15 | 35b3a662cd |
hex | 1e488acc13 |
130066074643 has 2 divisors, whose sum is σ = 130066074644. Its totient is φ = 130066074642.
The previous prime is 130066074631. The next prime is 130066074689. The reversal of 130066074643 is 346470660031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130066074643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130066074596 and 130066074605.
It is not a weakly prime, because it can be changed into another prime (130066074623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65033037321 + 65033037322.
It is an arithmetic number, because the mean of its divisors is an integer number (65033037322).
Almost surely, 2130066074643 is an apocalyptic number.
130066074643 is a deficient number, since it is larger than the sum of its proper divisors (1).
130066074643 is an equidigital number, since it uses as much as digits as its factorization.
130066074643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 40.
The spelling of 130066074643 in words is "one hundred thirty billion, sixty-six million, seventy-four thousand, six hundred forty-three".
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