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13008645437 is a prime number
BaseRepresentation
bin11000001110110000…
…00010110100111101
31020120121001122202212
430013120002310331
5203120203123222
65550500230205
7640236442664
oct140730026475
936517048685
1013008645437
11557604a947
12263069b365
1312c410ab48
148b5979ddb
155120ad6e2
hex307602d3d

13008645437 has 2 divisors, whose sum is σ = 13008645438. Its totient is φ = 13008645436.

The previous prime is 13008645373. The next prime is 13008645443. The reversal of 13008645437 is 73454680031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10690319236 + 2318326201 = 103394^2 + 48149^2 .

It is a cyclic number.

It is not a de Polignac number, because 13008645437 - 26 = 13008645373 is a prime.

It is a super-2 number, since 2×130086454372 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13008645394 and 13008645403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13008645467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6504322718 + 6504322719.

It is an arithmetic number, because the mean of its divisors is an integer number (6504322719).

Almost surely, 213008645437 is an apocalyptic number.

It is an amenable number.

13008645437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13008645437 is an equidigital number, since it uses as much as digits as its factorization.

13008645437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 41.

The spelling of 13008645437 in words is "thirteen billion, eight million, six hundred forty-five thousand, four hundred thirty-seven".