Base | Representation |
---|---|
bin | 1111100000100… |
… | …00000111011101 |
3 | 100001210020011022 |
4 | 13300100013131 |
5 | 231300330222 |
6 | 20524133525 |
7 | 3136512332 |
oct | 760200735 |
9 | 301706138 |
10 | 130089437 |
11 | 67483135 |
12 | 376972a5 |
13 | 20c4a3ca |
14 | 133c4989 |
15 | b64a042 |
hex | 7c101dd |
130089437 has 2 divisors, whose sum is σ = 130089438. Its totient is φ = 130089436.
The previous prime is 130089391. The next prime is 130089499. The reversal of 130089437 is 734980031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110544196 + 19545241 = 10514^2 + 4421^2 .
It is a cyclic number.
It is not a de Polignac number, because 130089437 - 212 = 130085341 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 130089397 and 130089406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130080437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65044718 + 65044719.
It is an arithmetic number, because the mean of its divisors is an integer number (65044719).
Almost surely, 2130089437 is an apocalyptic number.
It is an amenable number.
130089437 is a deficient number, since it is larger than the sum of its proper divisors (1).
130089437 is an equidigital number, since it uses as much as digits as its factorization.
130089437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 35.
The square root of 130089437 is about 11405.6756485532. The cubic root of 130089437 is about 506.6958469940.
The spelling of 130089437 in words is "one hundred thirty million, eighty-nine thousand, four hundred thirty-seven".
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