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130094799045119 is a prime number
BaseRepresentation
bin11101100101001000001110…
…010010001100000111111111
3122001121221102020010202011222
4131211020032102030013333
5114022433122023420434
61140404420422303555
736255016253250266
oct3545101622140777
9561557366122158
10130094799045119
11384a7992550a07
12127112b0b87bbb
135778b6b70621c
14241a89c5ab5dd
1510090e6dd472e
hex76520e48c1ff

130094799045119 has 2 divisors, whose sum is σ = 130094799045120. Its totient is φ = 130094799045118.

The previous prime is 130094799045103. The next prime is 130094799045161. The reversal of 130094799045119 is 911540997490031.

It is a weak prime.

It is an emirp because it is prime and its reverse (911540997490031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130094799045119 - 24 = 130094799045103 is a prime.

It is a super-2 number, since 2×1300947990451192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130094799045199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65047399522559 + 65047399522560.

It is an arithmetic number, because the mean of its divisors is an integer number (65047399522560).

Almost surely, 2130094799045119 is an apocalyptic number.

130094799045119 is a deficient number, since it is larger than the sum of its proper divisors (1).

130094799045119 is an equidigital number, since it uses as much as digits as its factorization.

130094799045119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11022480, while the sum is 62.

The spelling of 130094799045119 in words is "one hundred thirty trillion, ninety-four billion, seven hundred ninety-nine million, forty-five thousand, one hundred nineteen".