130094799045131 has 4 divisors (see below), whose sum is σ = 130143000159000. Its totient is φ = 130046597931264.

The previous prime is 130094799045119. The next prime is 130094799045161. The reversal of 130094799045131 is 131540997490031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130094799045131 is a prime.

It is a super-3 number, since 3×130094799045131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130094799045161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24100552886 + ... + 24100558283.

It is an arithmetic number, because the mean of its divisors is an integer number (32535750039750).

Almost surely, 2^{130094799045131} is an apocalyptic number.

130094799045131 is a deficient number, since it is larger than the sum of its proper divisors (48201113869).

130094799045131 is an equidigital number, since it uses as much as digits as its factorization.

130094799045131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48201113868.

The product of its (nonzero) digits is 3674160, while the sum is 56.

The spelling of 130094799045131 in words is "one hundred thirty trillion, ninety-four billion, seven hundred ninety-nine million, forty-five thousand, one hundred thirty-one".