Base | Representation |
---|---|
bin | 11101100101001000001110… |
… | …010010001100001000001010 |
3 | 122001121221102020010202012101 |
4 | 131211020032102030020022 |
5 | 114022433122023421010 |
6 | 1140404420422304014 |
7 | 36255016253250313 |
oct | 3545101622141012 |
9 | 561557366122171 |
10 | 130094799045130 |
11 | 384a7992550a17 |
12 | 127112b0b8800a |
13 | 5778b6b70622a |
14 | 241a89c5ab60a |
15 | 10090e6dd473a |
hex | 76520e48c20a |
130094799045130 has 32 divisors (see below), whose sum is σ = 240295267548864. Its totient is φ = 50683747462656.
The previous prime is 130094799045119. The next prime is 130094799045161. The reversal of 130094799045130 is 31540997490031.
130094799045130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 428383684 + ... + 428687263.
It is an arithmetic number, because the mean of its divisors is an integer number (7509227110902).
Almost surely, 2130094799045130 is an apocalyptic number.
130094799045130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130094799045130 is a deficient number, since it is larger than the sum of its proper divisors (110200468503734).
130094799045130 is a wasteful number, since it uses less digits than its factorization.
130094799045130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 857071350.
The product of its (nonzero) digits is 3674160, while the sum is 55.
The spelling of 130094799045130 in words is "one hundred thirty trillion, ninety-four billion, seven hundred ninety-nine million, forty-five thousand, one hundred thirty".
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