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130094799045132 = 22310841233253761
BaseRepresentation
bin11101100101001000001110…
…010010001100001000001100
3122001121221102020010202012110
4131211020032102030020030
5114022433122023421012
61140404420422304020
736255016253250315
oct3545101622141014
9561557366122173
10130094799045132
11384a7992550a19
12127112b0b88010
135778b6b70622c
14241a89c5ab60c
1510090e6dd473c
hex76520e48c20c

130094799045132 has 12 divisors (see below), whose sum is σ = 303554531105336. Its totient is φ = 43364933015040.

The previous prime is 130094799045119. The next prime is 130094799045161. The reversal of 130094799045132 is 231540997490031.

130094799045132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (12).

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5420616626869 + ... + 5420616626892.

Almost surely, 2130094799045132 is an apocalyptic number.

130094799045132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130094799045132 is an abundant number, since it is smaller than the sum of its proper divisors (173459732060204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130094799045132 is a wasteful number, since it uses less digits than its factorization.

130094799045132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10841233253768 (or 10841233253766 counting only the distinct ones).

The product of its (nonzero) digits is 7348320, while the sum is 57.

The spelling of 130094799045132 in words is "one hundred thirty trillion, ninety-four billion, seven hundred ninety-nine million, forty-five thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 10841233253761 21682466507522 32523699761283 43364933015044 65047399522566 130094799045132