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130100112022212 = 223210135781108917
BaseRepresentation
bin11101100101001101001010…
…111101100101101011000100
3122001122110010111102221121100
4131211031022331211223010
5114023030012134202322
61140411055534020100
736255265025643363
oct3545151275455304
9561573114387540
10130100112022212
11384aa169596272
1212712334347630
135779507357557
14241ac4405d7da
15100930855edac
hex76534af65ac4

130100112022212 has 36 divisors (see below), whose sum is σ = 332120252976876. Its totient is φ = 42937330699200.

The previous prime is 130100112022193. The next prime is 130100112022271. The reversal of 130100112022212 is 212220211001031.

130100112022212 is a `hidden beast` number, since 130 + 100 + 11 + 202 + 221 + 2 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 95782354627716 + 34317757394496 = 9786846^2 + 5858136^2 .

It is a tau number, because it is divible by the number of its divisors (36).

It is a super-2 number, since 2×1301001120222122 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17890550823 + ... + 17890558094.

It is an arithmetic number, because the mean of its divisors is an integer number (9225562582691).

Almost surely, 2130100112022212 is an apocalyptic number.

130100112022212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130100112022212 is an abundant number, since it is smaller than the sum of its proper divisors (202020140954664).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130100112022212 is a wasteful number, since it uses less digits than its factorization.

130100112022212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35781109028 (or 35781109023 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 130100112022212 its reverse (212220211001031), we get a palindrome (342320323023243).

The spelling of 130100112022212 in words is "one hundred thirty trillion, one hundred billion, one hundred twelve million, twenty-two thousand, two hundred twelve".

Divisors: 1 2 3 4 6 9 12 18 36 101 202 303 404 606 909 1212 1818 3636 35781108917 71562217834 107343326751 143124435668 214686653502 322029980253 429373307004 644059960506 1288119921012 3613892000617 7227784001234 10841676001851 14455568002468 21683352003702 32525028005553 43366704007404 65050056011106 130100112022212