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13010011232989 is a prime number
BaseRepresentation
bin1011110101010010000100…
…0110010001101011011101
31201001202010001101212011111
42331110201012101223131
53201124000333423424
643400414444022021
72511641130566521
oct275244106215335
951052101355144
1013010011232989
114166573197271
121561516531911
13734ab9aa9714
1432d98b86dd81
15178648513194
hexbd521191add

13010011232989 has 2 divisors, whose sum is σ = 13010011232990. Its totient is φ = 13010011232988.

The previous prime is 13010011232963. The next prime is 13010011233013. The reversal of 13010011232989 is 98923211001031.

13010011232989 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12675615040089 + 334396192900 = 3560283^2 + 578270^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13010011232989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13010011232189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505005616494 + 6505005616495.

It is an arithmetic number, because the mean of its divisors is an integer number (6505005616495).

Almost surely, 213010011232989 is an apocalyptic number.

It is an amenable number.

13010011232989 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010011232989 is an equidigital number, since it uses as much as digits as its factorization.

13010011232989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 40.

The spelling of 13010011232989 in words is "thirteen trillion, ten billion, eleven million, two hundred thirty-two thousand, nine hundred eighty-nine".