13010012232017 has 2 divisors, whose sum is σ = 13010012232018. Its totient is φ = 13010012232016.

The previous prime is 13010012232013. The next prime is 13010012232037. The reversal of 13010012232017 is 71023221001031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8214420298561 + 4795591933456 = 2866081^2 + 2189884^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010012232017 - 2² = 13010012232013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13010012231983 and 13010012232001.

It is not a weakly prime, because it can be changed into another prime (13010012232013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505006116008 + 6505006116009.

It is an arithmetic number, because the mean of its divisors is an integer number (6505006116009).

Almost surely, 2^{13010012232017} is an apocalyptic number.

It is an amenable number.

13010012232017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010012232017 is an equidigital number, since it uses as much as digits as its factorization.

13010012232017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 13010012232017 its reverse (71023221001031), we get a palindrome (84033233233048).

The spelling of 13010012232017 in words is "thirteen trillion, ten billion, twelve million, two hundred thirty-two thousand, seventeen".