Base | Representation |
---|---|
bin | 1011110101010010000100… |
… | …1010000101100101100101 |
3 | 1201001202010010021121121021 |
4 | 2331110201022011211211 |
5 | 3201124001112411122 |
6 | 43400414521251141 |
7 | 2511641142230302 |
oct | 275244112054545 |
9 | 51052103247537 |
10 | 13010012232037 |
11 | 4166573809927 |
12 | 1561516933ab1 |
13 | 734aba069382 |
14 | 32d98ba500a9 |
15 | 17864865e1c7 |
hex | bd521285965 |
13010012232037 has 2 divisors, whose sum is σ = 13010012232038. Its totient is φ = 13010012232036.
The previous prime is 13010012232017. The next prime is 13010012232067. The reversal of 13010012232037 is 73023221001031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10125130364001 + 2884881868036 = 3182001^2 + 1698494^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13010012232037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13010012232017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505006116018 + 6505006116019.
It is an arithmetic number, because the mean of its divisors is an integer number (6505006116019).
Almost surely, 213010012232037 is an apocalyptic number.
It is an amenable number.
13010012232037 is a deficient number, since it is larger than the sum of its proper divisors (1).
13010012232037 is an equidigital number, since it uses as much as digits as its factorization.
13010012232037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 13010012232037 its reverse (73023221001031), we get a palindrome (86033233233068).
The spelling of 13010012232037 in words is "thirteen trillion, ten billion, twelve million, two hundred thirty-two thousand, thirty-seven".
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