Base | Representation |
---|---|
bin | 10010111011101001110… |
… | …101110001111001011011 |
3 | 11121101010011021000112221 |
4 | 102323221311301321123 |
5 | 132303423322001411 |
6 | 2433401144044511 |
7 | 162665034460363 |
oct | 22735165617133 |
9 | 4541104230487 |
10 | 1301003312731 |
11 | 4618304a8971 |
12 | 190187463737 |
13 | 958b7c24405 |
14 | 46d7c9199a3 |
15 | 23c9705d071 |
hex | 12ee9d71e5b |
1301003312731 has 2 divisors, whose sum is σ = 1301003312732. Its totient is φ = 1301003312730.
The previous prime is 1301003312723. The next prime is 1301003312737. The reversal of 1301003312731 is 1372133001031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1301003312731 - 23 = 1301003312723 is a prime.
It is a super-2 number, since 2×13010033127312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1301003312696 and 1301003312705.
It is not a weakly prime, because it can be changed into another prime (1301003312737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650501656365 + 650501656366.
It is an arithmetic number, because the mean of its divisors is an integer number (650501656366).
Almost surely, 21301003312731 is an apocalyptic number.
1301003312731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301003312731 is an equidigital number, since it uses as much as digits as its factorization.
1301003312731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1301003312731 its reverse (1372133001031), we get a palindrome (2673136313762).
The spelling of 1301003312731 in words is "one trillion, three hundred one billion, three million, three hundred twelve thousand, seven hundred thirty-one".
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