1301004013 has 2 divisors, whose sum is σ = 1301004014. Its totient is φ = 1301004012.

The previous prime is 1301004007. The next prime is 1301004031. The reversal of 1301004013 is 3104001031.

Together with next prime (1301004031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1064521129 + 236482884 = 32627^2 + 15378^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301004013 - 2¹⁷ = 1300872941 is a prime.

It is a super-2 number, since 2×1301004013² = 3385222883684208338, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1301003984 and 1301004002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301004083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650502006 + 650502007.

It is an arithmetic number, because the mean of its divisors is an integer number (650502007).

Almost surely, 2^1301004013 is an apocalyptic number.

It is an amenable number.

1301004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301004013 is an equidigital number, since it uses as much as digits as its factorization.

1301004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1301004013 is about 36069.4332226055. The cubic root of 1301004013 is about 1091.6737781044.

Adding to 1301004013 its reverse (3104001031), we get a palindrome (4405005044).

The spelling of 1301004013 in words is "one billion, three hundred one million, four thousand, thirteen".