13010043101 has 8 divisors (see below), whose sum is σ = 15027643584. Its totient is φ = 11131587520.

The previous prime is 13010043097. The next prime is 13010043103. The reversal of 13010043101 is 10134001031.

13010043101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13010043101 - 2² = 13010043097 is a prime.

It is a super-4 number, since 4×13010043101⁴ (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13010043103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34786025 + ... + 34786398.

It is an arithmetic number, because the mean of its divisors is an integer number (1878455448).

Almost surely, 2^13010043101 is an apocalyptic number.

13010043101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13010043101 is a deficient number, since it is larger than the sum of its proper divisors (2017600483).

13010043101 is a wasteful number, since it uses less digits than its factorization.

13010043101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69572451.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13010043101 its reverse (10134001031), we get a palindrome (23144044132).

The spelling of 13010043101 in words is "thirteen billion, ten million, forty-three thousand, one hundred one".