13010043100 has 18 divisors (see below), whose sum is σ = 28231793744. Its totient is φ = 5204017200.

The previous prime is 13010043097. The next prime is 13010043103. The reversal of 13010043100 is 134001031.

It is an interprime number because it is at equal distance from previous prime (13010043097) and next prime (13010043103).

It is a super-2 number, since 2×13010043100² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13010043103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65050116 + ... + 65050315.

Almost surely, 2^13010043100 is an apocalyptic number.

13010043100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13010043100 is an abundant number, since it is smaller than the sum of its proper divisors (15221750644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13010043100 is a wasteful number, since it uses less digits than its factorization.

13010043100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130100445 (or 130100438 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13010043100 its reverse (134001031), we get a palindrome (13144044131).

The spelling of 13010043100 in words is "thirteen billion, ten million, forty-three thousand, one hundred".