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13010043103 is a prime number
BaseRepresentation
bin11000001110111010…
…11000000011011111
31020120200200200000021
430013131120003133
5203121032334403
65550550213011
7640254353551
oct140735300337
936520620007
1013010043103
115576914a42
122631054167
1312c44aa075
148b5c214d1
155122878bd
hex3077580df

13010043103 has 2 divisors, whose sum is σ = 13010043104. Its totient is φ = 13010043102.

The previous prime is 13010043097. The next prime is 13010043113. The reversal of 13010043103 is 30134001031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13010043103 is a prime.

It is a super-4 number, since 4×130100431034 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13010043113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505021551 + 6505021552.

It is an arithmetic number, because the mean of its divisors is an integer number (6505021552).

Almost surely, 213010043103 is an apocalyptic number.

13010043103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010043103 is an equidigital number, since it uses as much as digits as its factorization.

13010043103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13010043103 its reverse (30134001031), we get a palindrome (43144044134).

The spelling of 13010043103 in words is "thirteen billion, ten million, forty-three thousand, one hundred three".