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130100479043 is a prime number
BaseRepresentation
bin111100100101010010…
…1111100010001000011
3110102210221000002221212
41321022211330101003
54112421210312133
6135433424440335
712254003553113
oct1711245742103
9412727002855
10130100479043
11501a2368567
122126a4790ab
13c3649553a2
146422983043
1535b6ab0148
hex1e4a97c443

130100479043 has 2 divisors, whose sum is σ = 130100479044. Its totient is φ = 130100479042.

The previous prime is 130100478971. The next prime is 130100479051. The reversal of 130100479043 is 340974001031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130100479043 - 218 = 130100216899 is a prime.

It is a super-2 number, since 2×1301004790432 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130100479073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65050239521 + 65050239522.

It is an arithmetic number, because the mean of its divisors is an integer number (65050239522).

Almost surely, 2130100479043 is an apocalyptic number.

130100479043 is a deficient number, since it is larger than the sum of its proper divisors (1).

130100479043 is an equidigital number, since it uses as much as digits as its factorization.

130100479043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 32.

The spelling of 130100479043 in words is "one hundred thirty billion, one hundred million, four hundred seventy-nine thousand, forty-three".