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13010119973 is a prime number
BaseRepresentation
bin11000001110111011…
…01010110100100101
31020120200211120110022
430013131222310211
5203121042314343
65550552004525
7640255123634
oct140735526445
936520746408
1013010119973
115576967774
122631090745
1312c4506056
148b5c4151b
155122a0568
hex30776ad25

13010119973 has 2 divisors, whose sum is σ = 13010119974. Its totient is φ = 13010119972.

The previous prime is 13010119957. The next prime is 13010119999. The reversal of 13010119973 is 37991101031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12967060129 + 43059844 = 113873^2 + 6562^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010119973 - 24 = 13010119957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13010119943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505059986 + 6505059987.

It is an arithmetic number, because the mean of its divisors is an integer number (6505059987).

Almost surely, 213010119973 is an apocalyptic number.

It is an amenable number.

13010119973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010119973 is an equidigital number, since it uses as much as digits as its factorization.

13010119973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5103, while the sum is 35.

The spelling of 13010119973 in words is "thirteen billion, ten million, one hundred nineteen thousand, nine hundred seventy-three".