1301012100251 has 2 divisors, whose sum is σ = 1301012100252. Its totient is φ = 1301012100250.

The previous prime is 1301012100229. The next prime is 1301012100253. The reversal of 1301012100251 is 1520012101031.

It is a strong prime.

It is an emirp because it is prime and its reverse (1520012101031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1301012100251 - 2¹⁴ = 1301012083867 is a prime.

Together with 1301012100253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1301012100253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650506050125 + 650506050126.

It is an arithmetic number, because the mean of its divisors is an integer number (650506050126).

Almost surely, 2^{1301012100251} is an apocalyptic number.

1301012100251 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301012100251 is an equidigital number, since it uses as much as digits as its factorization.

1301012100251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 1301012100251 its reverse (1520012101031), we get a palindrome (2821024201282).

The spelling of 1301012100251 in words is "one trillion, three hundred one billion, twelve million, one hundred thousand, two hundred fifty-one".