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130101551 is a prime number
BaseRepresentation
bin1111100000100…
…11000100101111
3100001210211202222
413300103010233
5231301222201
620524305555
73136562546
oct760230457
9301724688
10130101551
1167491248
12376a22bb
1320c52a88
14133c915d
15b64d91b
hex7c1312f

130101551 has 2 divisors, whose sum is σ = 130101552. Its totient is φ = 130101550.

The previous prime is 130101539. The next prime is 130101557. The reversal of 130101551 is 155101031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130101551 - 214 = 130085167 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130101557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65050775 + 65050776.

It is an arithmetic number, because the mean of its divisors is an integer number (65050776).

Almost surely, 2130101551 is an apocalyptic number.

130101551 is a deficient number, since it is larger than the sum of its proper divisors (1).

130101551 is an equidigital number, since it uses as much as digits as its factorization.

130101551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 130101551 is about 11406.2066875890. The cubic root of 130101551 is about 506.7115744379.

Adding to 130101551 its reverse (155101031), we get a palindrome (285202582).

The spelling of 130101551 in words is "one hundred thirty million, one hundred one thousand, five hundred fifty-one".