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130102647439 is a prime number
BaseRepresentation
bin111100100101010111…
…0001101101010001111
3110102211002002021102211
41321022232031222033
54112422234204224
6135433543131251
712254031154012
oct1711256155217
9412732067384
10130102647439
11501a3609726
122126b143b27
13c36523436b
146422d89379
1535b6d8c894
hex1e4ab8da8f

130102647439 has 2 divisors, whose sum is σ = 130102647440. Its totient is φ = 130102647438.

The previous prime is 130102647371. The next prime is 130102647463. The reversal of 130102647439 is 934746201031.

It is a strong prime.

It is an emirp because it is prime and its reverse (934746201031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130102647439 - 223 = 130094258831 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130102647469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051323719 + 65051323720.

It is an arithmetic number, because the mean of its divisors is an integer number (65051323720).

Almost surely, 2130102647439 is an apocalyptic number.

130102647439 is a deficient number, since it is larger than the sum of its proper divisors (1).

130102647439 is an equidigital number, since it uses as much as digits as its factorization.

130102647439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 130102647439 in words is "one hundred thirty billion, one hundred two million, six hundred forty-seven thousand, four hundred thirty-nine".