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130103241203153 is a prime number
BaseRepresentation
bin11101100101010000000101…
…011110011101110111010001
3122001122202012120112210212202
4131211100011132131313101
5114023102414222000103
61140412334235132545
736255435413356031
oct3545200536356721
9561582176483782
10130103241203153
1138500524969219
1212712a682a4155
1357798b572b7ca
14241b05d8918c1
15100943d11e988
hex76540579ddd1

130103241203153 has 2 divisors, whose sum is σ = 130103241203154. Its totient is φ = 130103241203152.

The previous prime is 130103241203149. The next prime is 130103241203209. The reversal of 130103241203153 is 351302142301031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129927808393744 + 175432809409 = 11398588^2 + 418847^2 .

It is a cyclic number.

It is not a de Polignac number, because 130103241203153 - 22 = 130103241203149 is a prime.

It is not a weakly prime, because it can be changed into another prime (130103241203113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051620601576 + 65051620601577.

It is an arithmetic number, because the mean of its divisors is an integer number (65051620601577).

Almost surely, 2130103241203153 is an apocalyptic number.

It is an amenable number.

130103241203153 is a deficient number, since it is larger than the sum of its proper divisors (1).

130103241203153 is an equidigital number, since it uses as much as digits as its factorization.

130103241203153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 130103241203153 its reverse (351302142301031), we get a palindrome (481405383504184).

The spelling of 130103241203153 in words is "one hundred thirty trillion, one hundred three billion, two hundred forty-one million, two hundred three thousand, one hundred fifty-three".