Base | Representation |
---|---|
bin | 111100100101011000… |
… | …0101111011011000111 |
3 | 110102211010022221022222 |
4 | 1321022300233123013 |
5 | 4112422421410043 |
6 | 135434005242555 |
7 | 12254036613521 |
oct | 1711260573307 |
9 | 412733287288 |
10 | 130103310023 |
11 | 501a3a21515 |
12 | 2126b40345b |
13 | c365406b1b |
14 | 64230bca11 |
15 | 35b6e6dd68 |
hex | 1e4ac2f6c7 |
130103310023 has 2 divisors, whose sum is σ = 130103310024. Its totient is φ = 130103310022.
The previous prime is 130103310017. The next prime is 130103310031. The reversal of 130103310023 is 320013301031.
It is a weak prime.
It is an emirp because it is prime and its reverse (320013301031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130103310023 - 222 = 130099115719 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130103309983 and 130103310010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130103310223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051655011 + 65051655012.
It is an arithmetic number, because the mean of its divisors is an integer number (65051655012).
Almost surely, 2130103310023 is an apocalyptic number.
130103310023 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103310023 is an equidigital number, since it uses as much as digits as its factorization.
130103310023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 130103310023 its reverse (320013301031), we get a palindrome (450116611054).
The spelling of 130103310023 in words is "one hundred thirty billion, one hundred three million, three hundred ten thousand, twenty-three".
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