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130110317101 is a prime number
BaseRepresentation
bin111100100101100101…
…1011110001000101101
3110102211121111221020101
41321023023132020231
54112431220121401
6135434415351101
712254153306362
oct1711313361055
9412747457211
10130110317101
11501a7977a96
1221271822491
13c3669bb31b
146423dc4469
1535b78a5101
hex1e4b2de22d

130110317101 has 2 divisors, whose sum is σ = 130110317102. Its totient is φ = 130110317100.

The previous prime is 130110317087. The next prime is 130110317137. The reversal of 130110317101 is 101713011031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129592800100 + 517517001 = 359990^2 + 22749^2 .

It is an emirp because it is prime and its reverse (101713011031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130110317101 - 235 = 95750578733 is a prime.

It is a super-2 number, since 2×1301103171012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130110317191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055158550 + 65055158551.

It is an arithmetic number, because the mean of its divisors is an integer number (65055158551).

Almost surely, 2130110317101 is an apocalyptic number.

It is an amenable number.

130110317101 is a deficient number, since it is larger than the sum of its proper divisors (1).

130110317101 is an equidigital number, since it uses as much as digits as its factorization.

130110317101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63, while the sum is 19.

Adding to 130110317101 its reverse (101713011031), we get a palindrome (231823328132).

The spelling of 130110317101 in words is "one hundred thirty billion, one hundred ten million, three hundred seventeen thousand, one hundred one".