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13011042012 = 2231084253501
BaseRepresentation
bin11000001111000010…
…01011111011011100
31020120202120102020220
430013201023323130
5203121311321022
65551023441340
7640266014043
oct140741137334
936522512226
1013011042012
115577437491
122631456250
1312c4769937
148b600155a
155123d385c
hex30784bedc

13011042012 has 12 divisors (see below), whose sum is σ = 30359098056. Its totient is φ = 4337014000.

The previous prime is 13011041993. The next prime is 13011042029. The reversal of 13011042012 is 21024011031.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 13011041982 and 13011042000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542126739 + ... + 542126762.

It is an arithmetic number, because the mean of its divisors is an integer number (2529924838).

Almost surely, 213011042012 is an apocalyptic number.

13011042012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13011042012 is an abundant number, since it is smaller than the sum of its proper divisors (17348056044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011042012 is a wasteful number, since it uses less digits than its factorization.

13011042012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1084253508 (or 1084253506 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13011042012 its reverse (21024011031), we get a palindrome (34035053043).

The spelling of 13011042012 in words is "thirteen billion, eleven million, forty-two thousand, twelve".

Divisors: 1 2 3 4 6 12 1084253501 2168507002 3252760503 4337014004 6505521006 13011042012