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13011103319 is a prime number
BaseRepresentation
bin11000001111000010…
…11010111001010111
31020120202200112100112
430013201122321113
5203121320301234
65551025033235
7640266360554
oct140741327127
936522615315
1013011103319
115577479555
12263148581b
1312c478b806
148b6019a2b
155123e6ace
hex30785ae57

13011103319 has 2 divisors, whose sum is σ = 13011103320. Its totient is φ = 13011103318.

The previous prime is 13011103249. The next prime is 13011103333. The reversal of 13011103319 is 91330111031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13011103319 is a prime.

It is a super-2 number, since 2×130111033192 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13011103294 and 13011103303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011103349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505551659 + 6505551660.

It is an arithmetic number, because the mean of its divisors is an integer number (6505551660).

Almost surely, 213011103319 is an apocalyptic number.

13011103319 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011103319 is an equidigital number, since it uses as much as digits as its factorization.

13011103319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 13011103319 in words is "thirteen billion, eleven million, one hundred three thousand, three hundred nineteen".