Base | Representation |
---|---|
bin | 11101100101010111011001… |
… | …111101101000111111010101 |
3 | 122001200111111100100120020002 |
4 | 131211113121331220333111 |
5 | 114023220013341043102 |
6 | 1140420114212221045 |
7 | 36256134243450005 |
oct | 3545273175507725 |
9 | 561614440316202 |
10 | 130111101112277 |
11 | 3850389865228a |
12 | 127144a060a785 |
13 | 577a568c320cc |
14 | 241b5a76d0005 |
15 | 100974d196902 |
hex | 7655d9f68fd5 |
130111101112277 has 2 divisors, whose sum is σ = 130111101112278. Its totient is φ = 130111101112276.
The previous prime is 130111101112189. The next prime is 130111101112327. The reversal of 130111101112277 is 772211101111031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129853295111761 + 257806000516 = 11395319^2 + 507746^2 .
It is a cyclic number.
It is not a de Polignac number, because 130111101112277 - 210 = 130111101111253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130111101112477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055550556138 + 65055550556139.
It is an arithmetic number, because the mean of its divisors is an integer number (65055550556139).
Almost surely, 2130111101112277 is an apocalyptic number.
It is an amenable number.
130111101112277 is a deficient number, since it is larger than the sum of its proper divisors (1).
130111101112277 is an equidigital number, since it uses as much as digits as its factorization.
130111101112277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 588, while the sum is 29.
The spelling of 130111101112277 in words is "one hundred thirty trillion, one hundred eleven billion, one hundred one million, one hundred twelve thousand, two hundred seventy-seven".
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