Base | Representation |
---|---|
bin | 11101100101010111011011… |
… | …110100101100100111111110 |
3 | 122001200111120112002012022221 |
4 | 131211113123310230213332 |
5 | 114023220044333303202 |
6 | 1140420121245155554 |
7 | 36256135102645225 |
oct | 3545273364544776 |
9 | 561614515065287 |
10 | 130111132322302 |
11 | 3850390422989a |
12 | 127144aab5bbba |
13 | 577a57253ba91 |
14 | 241b5ab8d5cbc |
15 | 1009750cae037 |
hex | 7655dbd2c9fe |
130111132322302 has 4 divisors (see below), whose sum is σ = 195166698483456. Its totient is φ = 65055566161150.
The previous prime is 130111132322279. The next prime is 130111132322309. The reversal of 130111132322302 is 203223231111031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130111132322309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32527783080574 + ... + 32527783080577.
It is an arithmetic number, because the mean of its divisors is an integer number (48791674620864).
Almost surely, 2130111132322302 is an apocalyptic number.
130111132322302 is a deficient number, since it is larger than the sum of its proper divisors (65055566161154).
130111132322302 is an equidigital number, since it uses as much as digits as its factorization.
130111132322302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65055566161153.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 130111132322302 its reverse (203223231111031), we get a palindrome (333334363433333).
The spelling of 130111132322302 in words is "one hundred thirty trillion, one hundred eleven billion, one hundred thirty-two million, three hundred twenty-two thousand, three hundred two".
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