130111200113232 has 40 divisors (see below), whose sum is σ = 361976031085984. Its totient is φ = 40034215419264.

The previous prime is 130111200113221. The next prime is 130111200113287. The reversal of 130111200113232 is 232311002111031.

It is a super-4 number, since 4×130111200113232⁴ (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130111200113199 and 130111200113208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104255768698 + ... + 104255769945.

Almost surely, 2^{130111200113232} is an apocalyptic number.

130111200113232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130111200113232 is an abundant number, since it is smaller than the sum of its proper divisors (231864830972752).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130111200113232 is a wasteful number, since it uses less digits than its factorization.

130111200113232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 208511538667 (or 208511538661 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 130111200113232 its reverse (232311002111031), we get a palindrome (362422202224263).

The spelling of 130111200113232 in words is "one hundred thirty trillion, one hundred eleven billion, two hundred million, one hundred thirteen thousand, two hundred thirty-two".