Base | Representation |
---|---|
bin | 11000001111000010… |
… | …11111001111010111 |
3 | 1020120202201102202111 |
4 | 30013201133033113 |
5 | 203121321333421 |
6 | 5551025251451 |
7 | 640266463462 |
oct | 140741371727 |
9 | 36522642674 |
10 | 13011121111 |
11 | 557749095a |
12 | 2631493b87 |
13 | 12c4796941 |
14 | 8b60222d9 |
15 | 5123ebee1 |
hex | 30785f3d7 |
13011121111 has 2 divisors, whose sum is σ = 13011121112. Its totient is φ = 13011121110.
The previous prime is 13011121051. The next prime is 13011121129. The reversal of 13011121111 is 11112111031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13011121111 - 211 = 13011119063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13011121091 and 13011121100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13011121811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505560555 + 6505560556.
It is an arithmetic number, because the mean of its divisors is an integer number (6505560556).
Almost surely, 213011121111 is an apocalyptic number.
13011121111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011121111 is an equidigital number, since it uses as much as digits as its factorization.
13011121111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 13011121111 its reverse (11112111031), we get a palindrome (24123232142).
The spelling of 13011121111 in words is "thirteen billion, eleven million, one hundred twenty-one thousand, one hundred eleven".
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