Base | Representation |
---|---|
bin | 111100100101100111… |
… | …1010110001010011100 |
3 | 110102211200102112211000 |
4 | 1321023033112022130 |
5 | 4112432000124040 |
6 | 135434453230300 |
7 | 12254165040264 |
oct | 1711317261234 |
9 | 412750375730 |
10 | 130111333020 |
11 | 501a8501299 |
12 | 21272032390 |
13 | c366c85866 |
14 | 64241aa7a4 |
15 | 35b7a06130 |
hex | 1e4b3d629c |
130111333020 has 192 divisors, whose sum is σ = 410353735680. Its totient is φ = 34222176000.
The previous prime is 130111332973. The next prime is 130111333049. The reversal of 130111333020 is 20333111031.
It is a happy number.
130111333020 is a `hidden beast` number, since 1 + 301 + 1 + 13 + 330 + 20 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 130111332984 and 130111333002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14775939 + ... + 14784741.
It is an arithmetic number, because the mean of its divisors is an integer number (2137259040).
Almost surely, 2130111333020 is an apocalyptic number.
130111333020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130111333020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (205176867840).
130111333020 is an abundant number, since it is smaller than the sum of its proper divisors (280242402660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130111333020 is a wasteful number, since it uses less digits than its factorization.
130111333020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9193 (or 9185 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 130111333020 its reverse (20333111031), we get a palindrome (150444444051).
The spelling of 130111333020 in words is "one hundred thirty billion, one hundred eleven million, three hundred thirty-three thousand, twenty".
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