13011201201101 has 2 divisors, whose sum is σ = 13011201201102. Its totient is φ = 13011201201100.

The previous prime is 13011201201079. The next prime is 13011201201109. The reversal of 13011201201101 is 10110210211031.

13011201201101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10440983025001 + 2570218176100 = 3231251^2 + 1603190^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011201201101 - 2¹⁰ = 13011201200077 is a prime.

It is a super-2 number, since 2×13011201201101² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011201201109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505600600550 + 6505600600551.

It is an arithmetic number, because the mean of its divisors is an integer number (6505600600551).

Almost surely, 2^{13011201201101} is an apocalyptic number.

It is an amenable number.

13011201201101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011201201101 is an equidigital number, since it uses as much as digits as its factorization.

13011201201101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 13011201201101 its reverse (10110210211031), we get a palindrome (23121411412132).

The spelling of 13011201201101 in words is "thirteen trillion, eleven billion, two hundred one million, two hundred one thousand, one hundred one".