130112030113333 has 4 divisors (see below), whose sum is σ = 131453391248620. Its totient is φ = 128770668978048.

The previous prime is 130112030113321. The next prime is 130112030113337. The reversal of 130112030113333 is 333311030211031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74882058447364 + 55229971665969 = 8653442^2 + 7431687^2 .

It is a cyclic number.

It is not a de Polignac number, because 130112030113333 - 2⁵ = 130112030113301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130112030113298 and 130112030113307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130112030113337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670680567498 + ... + 670680567691.

It is an arithmetic number, because the mean of its divisors is an integer number (32863347812155).

Almost surely, 2^{130112030113333} is an apocalyptic number.

It is an amenable number.

130112030113333 is a deficient number, since it is larger than the sum of its proper divisors (1341361135287).

130112030113333 is an equidigital number, since it uses as much as digits as its factorization.

130112030113333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1341361135286.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 130112030113333 its reverse (333311030211031), we get a palindrome (463423060324364).

The spelling of 130112030113333 in words is "one hundred thirty trillion, one hundred twelve billion, thirty million, one hundred thirteen thousand, three hundred thirty-three".