Base | Representation |
---|---|
bin | 1011110101010110100000… |
… | …1001010001101111001111 |
3 | 1201001212012010022011020212 |
4 | 2331111220021101233033 |
5 | 3201133421004430444 |
6 | 43401133024033035 |
7 | 2512012513266032 |
oct | 275255011215717 |
9 | 51055163264225 |
10 | 13011203201999 |
11 | 4167025008222 |
12 | 15617a976277b |
13 | 734c49a1b622 |
14 | 32da61cad019 |
15 | 1786b7eb419e |
hex | bd568251bcf |
13011203201999 has 2 divisors, whose sum is σ = 13011203202000. Its totient is φ = 13011203201998.
The previous prime is 13011203201987. The next prime is 13011203202059. The reversal of 13011203201999 is 99910230211031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13011203201999 - 220 = 13011202153423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13011203201959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505601600999 + 6505601601000.
It is an arithmetic number, because the mean of its divisors is an integer number (6505601601000).
Almost surely, 213011203201999 is an apocalyptic number.
13011203201999 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011203201999 is an equidigital number, since it uses as much as digits as its factorization.
13011203201999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 41.
The spelling of 13011203201999 in words is "thirteen trillion, eleven billion, two hundred three million, two hundred one thousand, nine hundred ninety-nine".
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