Base | Representation |
---|---|
bin | 111100100101101001… |
… | …1000101011100001100 |
3 | 110102211202021100020021 |
4 | 1321023103011130030 |
5 | 4112432223004400 |
6 | 135434530231524 |
7 | 12254206261540 |
oct | 1711323053414 |
9 | 412752240207 |
10 | 130112313100 |
11 | 501a9010680 |
12 | 212724255a4 |
13 | c3672399a3 |
14 | 6424383a20 |
15 | 35b7b4b71a |
hex | 1e4b4c570c |
130112313100 has 72 divisors (see below), whose sum is σ = 352012969728. Its totient is φ = 40554484800.
The previous prime is 130112313077. The next prime is 130112313103. The reversal of 130112313100 is 1313211031.
It is a super-2 number, since 2×1301123131002 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130112313103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8441152 + ... + 8456551.
It is an arithmetic number, because the mean of its divisors is an integer number (4889069024).
Almost surely, 2130112313100 is an apocalyptic number.
130112313100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130112313100 is an abundant number, since it is smaller than the sum of its proper divisors (221900656628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130112313100 is a wasteful number, since it uses less digits than its factorization.
130112313100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16897735 (or 16897728 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 130112313100 its reverse (1313211031), we get a palindrome (131425524131).
The spelling of 130112313100 in words is "one hundred thirty billion, one hundred twelve million, three hundred thirteen thousand, one hundred".
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