13011233531 has 2 divisors, whose sum is σ = 13011233532. Its totient is φ = 13011233530.

The previous prime is 13011233503. The next prime is 13011233533. The reversal of 13011233531 is 13533211031.

It is a strong prime.

It is an emirp because it is prime and its reverse (13533211031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13011233531 - 2¹⁴ = 13011217147 is a prime.

It is a super-2 number, since 2×13011233531² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13011233533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011233497 and 13011233506.

It is not a weakly prime, because it can be changed into another prime (13011233533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505616765 + 6505616766.

It is an arithmetic number, because the mean of its divisors is an integer number (6505616766).

Almost surely, 2^13011233531 is an apocalyptic number.

13011233531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011233531 is an equidigital number, since it uses as much as digits as its factorization.

13011233531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 23.

Adding to 13011233531 its reverse (13533211031), we get a palindrome (26544444562).

The spelling of 13011233531 in words is "thirteen billion, eleven million, two hundred thirty-three thousand, five hundred thirty-one".