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130113101222032 = 248132068826377
BaseRepresentation
bin11101100101011001010001…
…001011011101000010010000
3122001200200122201220200000011
4131211121101023131002100
5114023233112403101112
61140421044501404304
736256234641216535
oct3545312113350220
9561620581820004
10130113101222032
1138504724664355
121271495a409694
13577a7c74173c6
14241b7171b6d8c
151009818a7baa7
hex7656512dd090

130113101222032 has 10 divisors (see below), whose sum is σ = 252094133617718. Its totient is φ = 65056550611008.

The previous prime is 130113101222011. The next prime is 130113101222087. The reversal of 130113101222032 is 230222101311031.

It can be written as a sum of positive squares in only one way, i.e., 119746272522496 + 10366828699536 = 10942864^2 + 3219756^2 .

It is a super-2 number, since 2×1301131012220322 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130113101221994 and 130113101222012.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4066034413173 + ... + 4066034413204.

Almost surely, 2130113101222032 is an apocalyptic number.

It is an amenable number.

130113101222032 is a deficient number, since it is larger than the sum of its proper divisors (121981032395686).

130113101222032 is an equidigital number, since it uses as much as digits as its factorization.

130113101222032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8132068826385 (or 8132068826379 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 130113101222032 its reverse (230222101311031), we get a palindrome (360335202533063).

The spelling of 130113101222032 in words is "one hundred thirty trillion, one hundred thirteen billion, one hundred one million, two hundred twenty-two thousand, thirty-two".

Divisors: 1 2 4 8 16 8132068826377 16264137652754 32528275305508 65056550611016 130113101222032