Base | Representation |
---|---|
bin | 11101100101011001010001… |
… | …001011011101000011000111 |
3 | 122001200200122201220200002012 |
4 | 131211121101023131003013 |
5 | 114023233112403101322 |
6 | 1140421044501404435 |
7 | 36256234641216644 |
oct | 3545312113350307 |
9 | 561620581820065 |
10 | 130113101222087 |
11 | 385047246643a5 |
12 | 1271495a40971b |
13 | 577a7c7417439 |
14 | 241b7171b6dcb |
15 | 1009818a7bae2 |
hex | 7656512dd0c7 |
130113101222087 has 2 divisors, whose sum is σ = 130113101222088. Its totient is φ = 130113101222086.
The previous prime is 130113101222011. The next prime is 130113101222123. The reversal of 130113101222087 is 780222101311031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130113101222087 - 228 = 130112832786631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130113161222087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056550611043 + 65056550611044.
It is an arithmetic number, because the mean of its divisors is an integer number (65056550611044).
Almost surely, 2130113101222087 is an apocalyptic number.
130113101222087 is a deficient number, since it is larger than the sum of its proper divisors (1).
130113101222087 is an equidigital number, since it uses as much as digits as its factorization.
130113101222087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 32.
The spelling of 130113101222087 in words is "one hundred thirty trillion, one hundred thirteen billion, one hundred one million, two hundred twenty-two thousand, eighty-seven".
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