Base | Representation |
---|---|
bin | 1011110101010110111100… |
… | …1110100000011001111111 |
3 | 1201001212111101212101201211 |
4 | 2331111233032200121333 |
5 | 3201134141413411221 |
6 | 43401152510345251 |
7 | 2512015455206506 |
oct | 275255716403177 |
9 | 51055441771654 |
10 | 13011322013311 |
11 | 4167086087996 |
12 | 15618214bb227 |
13 | 734c6851a48b |
14 | 32da7399983d |
15 | 1786c36326e1 |
hex | bd56f3a067f |
13011322013311 has 2 divisors, whose sum is σ = 13011322013312. Its totient is φ = 13011322013310.
The previous prime is 13011322013293. The next prime is 13011322013321. The reversal of 13011322013311 is 11331022311031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13011322013311 - 217 = 13011321882239 is a prime.
It is a super-2 number, since 2×130113220133112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13011322013321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505661006655 + 6505661006656.
It is an arithmetic number, because the mean of its divisors is an integer number (6505661006656).
Almost surely, 213011322013311 is an apocalyptic number.
13011322013311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011322013311 is an equidigital number, since it uses as much as digits as its factorization.
13011322013311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13011322013311 its reverse (11331022311031), we get a palindrome (24342344324342).
The spelling of 13011322013311 in words is "thirteen trillion, eleven billion, three hundred twenty-two million, thirteen thousand, three hundred eleven".
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