13011330111120 has 240 divisors, whose sum is σ = 47672359488000. Its totient is φ = 3154025134080.

The previous prime is 13011330111103. The next prime is 13011330111137. The reversal of 13011330111120 is 2111103311031.

13011330111120 is a `hidden beast` number, since 1 + 301 + 1 + 330 + 1 + 1 + 11 + 20 = 666.

It is an interprime number because it is at equal distance from previous prime (13011330111103) and next prime (13011330111137).

It is a tau number, because it is divible by the number of its divisors (240).

It is a super-2 number, since 2×13011330111120² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13011330111093 and 13011330111102.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 120322036 + ... + 120430124.

It is an arithmetic number, because the mean of its divisors is an integer number (198634831200).

Almost surely, 2^{13011330111120} is an apocalyptic number.

13011330111120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13011330111120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23836179744000).

13011330111120 is an abundant number, since it is smaller than the sum of its proper divisors (34661029376880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011330111120 is a wasteful number, since it uses less digits than its factorization.

13011330111120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123318 (or 123309 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13011330111120 its reverse (2111103311031), we get a palindrome (15122433422151).

The spelling of 13011330111120 in words is "thirteen trillion, eleven billion, three hundred thirty million, one hundred eleven thousand, one hundred twenty".