Base | Representation |
---|---|
bin | 11000001111000100… |
… | …10111101111100011 |
3 | 1020120210011012020012 |
4 | 30013202113233203 |
5 | 203121401240142 |
6 | 5551034235135 |
7 | 640301446304 |
oct | 140742275743 |
9 | 36523135205 |
10 | 13011352547 |
11 | 5577629826 |
12 | 2631585aab |
13 | 12c484809b |
14 | 8b60827ab |
15 | 512445882 |
hex | 307897be3 |
13011352547 has 2 divisors, whose sum is σ = 13011352548. Its totient is φ = 13011352546.
The previous prime is 13011352511. The next prime is 13011352561. The reversal of 13011352547 is 74525311031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13011352547 - 212 = 13011348451 is a prime.
It is not a weakly prime, because it can be changed into another prime (13011352847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505676273 + 6505676274.
It is an arithmetic number, because the mean of its divisors is an integer number (6505676274).
Almost surely, 213011352547 is an apocalyptic number.
13011352547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011352547 is an equidigital number, since it uses as much as digits as its factorization.
13011352547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12600, while the sum is 32.
Adding to 13011352547 its reverse (74525311031), we get a palindrome (87536663578).
The spelling of 13011352547 in words is "thirteen billion, eleven million, three hundred fifty-two thousand, five hundred forty-seven".
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