130114121 has 2 divisors, whose sum is σ = 130114122. Its totient is φ = 130114120.

The previous prime is 130114091. The next prime is 130114129. The reversal of 130114121 is 121411031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124657225 + 5456896 = 11165^2 + 2336^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130114121 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130114096 and 130114105.

It is not a weakly prime, because it can be changed into another prime (130114129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65057060 + 65057061.

It is an arithmetic number, because the mean of its divisors is an integer number (65057061).

Almost surely, 2^130114121 is an apocalyptic number.

It is an amenable number.

130114121 is a deficient number, since it is larger than the sum of its proper divisors (1).

130114121 is an equidigital number, since it uses as much as digits as its factorization.

130114121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 130114121 is about 11406.7576900713. The cubic root of 130114121 is about 506.7278928684.

Adding to 130114121 its reverse (121411031), we get a palindrome (251525152).

The spelling of 130114121 in words is "one hundred thirty million, one hundred fourteen thousand, one hundred twenty-one".