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13011417031 is a prime number
BaseRepresentation
bin11000001111000101…
…00111011111000111
31020120210021110200111
430013202213133013
5203121410321111
65551035453451
7640302135304
oct140742473707
936523243614
1013011417031
115577673218
1226315b7287
1312c486b542
148b609c0ab
15512459a21
hex3078a77c7

13011417031 has 2 divisors, whose sum is σ = 13011417032. Its totient is φ = 13011417030.

The previous prime is 13011416989. The next prime is 13011417047. The reversal of 13011417031 is 13071411031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13011417031 - 29 = 13011416519 is a prime.

It is a super-2 number, since 2×130114170312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13011416993 and 13011417011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011487031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505708515 + 6505708516.

It is an arithmetic number, because the mean of its divisors is an integer number (6505708516).

Almost surely, 213011417031 is an apocalyptic number.

13011417031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011417031 is an equidigital number, since it uses as much as digits as its factorization.

13011417031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 13011417031 its reverse (13071411031), we get a palindrome (26082828062).

The spelling of 13011417031 in words is "thirteen billion, eleven million, four hundred seventeen thousand, thirty-one".