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130118117 is a prime number
BaseRepresentation
bin1111100000101…
…11000111100101
3100001211200111112
413300113013211
5231302234432
620524514405
73136662053
oct760270745
9301750445
10130118117
11674a2738
12376aba05
1320c5a48c
14133d11d3
15b6537b2
hex7c171e5

130118117 has 2 divisors, whose sum is σ = 130118118. Its totient is φ = 130118116.

The previous prime is 130118113. The next prime is 130118147. The reversal of 130118117 is 711811031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75933796 + 54184321 = 8714^2 + 7361^2 .

It is a cyclic number.

It is not a de Polignac number, because 130118117 - 22 = 130118113 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130118092 and 130118101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130118111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65059058 + 65059059.

It is an arithmetic number, because the mean of its divisors is an integer number (65059059).

Almost surely, 2130118117 is an apocalyptic number.

It is an amenable number.

130118117 is a deficient number, since it is larger than the sum of its proper divisors (1).

130118117 is an equidigital number, since it uses as much as digits as its factorization.

130118117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 23.

The square root of 130118117 is about 11406.9328480534. The cubic root of 130118117 is about 506.7330802735.

Adding to 130118117 its reverse (711811031), we get a palindrome (841929148).

The spelling of 130118117 in words is "one hundred thirty million, one hundred eighteen thousand, one hundred seventeen".